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-76=-3c^2-7
We move all terms to the left:
-76-(-3c^2-7)=0
We get rid of parentheses
3c^2+7-76=0
We add all the numbers together, and all the variables
3c^2-69=0
a = 3; b = 0; c = -69;
Δ = b2-4ac
Δ = 02-4·3·(-69)
Δ = 828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{828}=\sqrt{36*23}=\sqrt{36}*\sqrt{23}=6\sqrt{23}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{23}}{2*3}=\frac{0-6\sqrt{23}}{6} =-\frac{6\sqrt{23}}{6} =-\sqrt{23} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{23}}{2*3}=\frac{0+6\sqrt{23}}{6} =\frac{6\sqrt{23}}{6} =\sqrt{23} $
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